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24x^2-74x-35=0
a = 24; b = -74; c = -35;
Δ = b2-4ac
Δ = -742-4·24·(-35)
Δ = 8836
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{8836}=94$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-74)-94}{2*24}=\frac{-20}{48} =-5/12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-74)+94}{2*24}=\frac{168}{48} =3+1/2 $
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